Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 21 - Electromagnetic Induction and Faraday's Law - Problems - Page 621: 21

Answer

a. 810 V. b. To double the rms output voltage, double the rotation frequency to 240 rev/s.

Work Step by Step

a. The peak induced emf is calculated from equation 21–5. $$V_{peak}=NB\omega A$$ We find the rms voltage from the peak induced emf. $$V_{rms}=\frac{V_{peak}}{\sqrt{2}}=\frac{NB\omega A}{\sqrt{2}}$$ $$V_{rms}=\frac{(550)(0.55T)(2 \pi rad/rev)(120rev/s) \pi(0.040m)^2}{\sqrt{2}}=810V$$ b. To double the rms output voltage, double the rotation frequency to 240 rev/s.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.