Answer
(a) $\epsilon=1.73\times 10^{-2}V$
(b) $E=0.114\frac{V}{m}$ downward
Work Step by Step
(a)We can find emf as:
$\epsilon=Blv$
We plug in the known values to obtain:
$\epsilon=0.800\times 0.120\times 0.180=1.73\times 10^{-2}V$
(b) As the induced current is clockwise so the induced emf is downward and hence the electric field is also downwards. Therefore, we find electric field as:
$E=\frac{1.73\times 10^{-2}}{0.120}=0.114\frac{V}{m}$
