Answer
1.63 amperes
Work Step by Step
Use equation 20–2.
$$F_{max}=I\mathcal{l}B $$
$$I=\frac{F_{max}}{\mathcal{l}B}=\frac{0.625N}{(4.80m)(0.0800T)}=1.63A $$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 20 - Magnetism - Problems - Page 583: 2
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