Answer
$4.2\times10^{-4}N $
Work Step by Step
Use equation 20–1 to calculate the force.
$$F=I\mathcal{l}Bsin\theta$$
$$F= (4.5A)(2.6m)(5.5\times10^{-5}T)sin41^{\circ}=4.2\times10^{-4}N $$
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