Answer
61.8 m.
Work Step by Step
Choose downward to be the positive direction, and take y=0 at the top of the cliff. The initial velocity is v=0 and the acceleration is $9.8 \frac{m}{s^{2}}$.
Find the displacement from equation 2–11b.
$$y-0 = 0 +\frac{1}{2}(9.8 \frac{m}{s^{2}})(3.55 s)^{2} =61.8 m$$
