## Physics: Principles with Applications (7th Edition)

Choose downward to be the positive direction, and take y=0 at the top of the cliff. The initial velocity is v=0 and the acceleration is $9.8 \frac{m}{s^{2}}$. Find the displacement from equation 2–11b. $$y-0 = 0 +\frac{1}{2}(9.8 \frac{m}{s^{2}})(3.55 s)^{2} =61.8 m$$