## Physics: Principles with Applications (7th Edition)

a) 1.2 $m/s^2$ b) 106 m
a) We solve using the equation: v = $v_{o}$ + at a = $\frac{v-v_{o}}{t}$ a = $\frac{21m/s - 14m/s}{6.0s}$ a = 1.2 $m/s^2$ b) We solve using the equation: x = $v_{o}t + \frac{1}{2}at^2$ x = $(14m/s)(6.0s) + \frac{1}{2}(1.2m/s^2)(6.0s)^2$ x = 106m