# Chapter 2 - Describing Motion: Kinematics in One Dimension - Problems: 16

a. 0.065 h, 6.2 km. b. 0.00765 h, 0.73 km.

#### Work Step by Step

a. Write the distance that the car travels. d = (95 km/h)(t) Alternatively, the car must travel the length of the train plus the distance that the train travels. d = (train length) + (75 km/h)(t) Set the two expressions equal, and solve for the time of 0.065 hours. Plug that time back into either distance expression above to find the car’s travel distance. b. Now the car travels the length of the train MINUS the distance that the train travels. The second expression above now becomes d = (train length) - (75 km/h)(t). Once again, equate the two expressions for the distance the car travels, and solve for the time. Plug that time back into either distance expression to find the car’s travel distance in this second case.

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