Answer
$$1 \times 10^{5} \frac{km}{h}$$
Work Step by Step
Average speed is the distance divided by the time.
$$1 \times 10^{9} \frac{km}{yr} \frac{1 year}{365.25 days} \frac{1 day}{24 h}= 1 \times 10^{5} \frac{km}{h}$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 2 - Describing Motion: Kinematics in One Dimension - Problems - Page 43: 10
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