Answer
a. 5.92 V
b. 5.99 V
Work Step by Step
Example 19-1 and Figure 19–2 treat this problem. Do the problem the same way, using equation 19–1 to calculate the terminal voltage.
a. $V_{ab}=\epsilon\frac{R}{R+r}=(6.00V)\frac{71.0\Omega}{71.0\Omega+0.900\Omega}=5.92V$
b. $V_{ab}=\epsilon\frac{R}{R+r}=(6.00V)\frac{710\Omega}{710\Omega+0.900\Omega}=5.99V$
