Answer
(a) The voltage across each bulb is 15 V
(b) The resistance of each bulb is $33.3~\Omega$
The power dissipated in each bulb is 6.75 W
Work Step by Step
(a) Since the bulbs are identical and in series, the voltage across each bulb will be the same. Let $V_0$ be the voltage across each bulb.
$8~V_0= 120~V$
$V_0 = 15~V$
The voltage across each bulb is 15 V.
(b) We can find the resistance $R_0$ of each bulb.
$V_0 = I~R_0$
$R_0 = \frac{V_0}{I}$
$R_0 = \frac{15~V}{0.45~A}$
$R_0 = 33.3~\Omega$
The resistance of each bulb is $33.3~\Omega$.
We can find the power dissipated in each bulb.
$P = I~V$
$P = (0.45~A)(15~V)$
$P = 6.75~W$
The power dissipated in each bulb is 6.75 W.
