Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - General Problems - Page 524: 70

Answer

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Work Step by Step

a. Calculate the resistance at the operating temperature from the power and voltage. $$P=\frac{V^2}{R}$$ $$R=\frac{V^2}{P}=\frac{(120V)^2}{75W}=190\Omega$$ b. Calculate the resistance at room temperature is found by using equation 18–4. $$R=R_0(1+\alpha(T-T_0))$$ $$R_0=\frac{R}{(1+\alpha(T-T_0))}=\frac{192\Omega}{1+(0.0045K^{-1})(2800K-293K)}\approx16\Omega$$
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