Answer
a. $5.8\times10^5V$
b. $9.2\times10^{-14}J$
Work Step by Step
a. Use equation 17–5 to find the potential of a point charge.
$$V=\frac{1}{4\pi\epsilon_o}\frac{Q}{r}$$
$$V=(8.99\times10^9\frac{N\cdot m^2}{C^2})\frac{1.60\times10^{-19}C}{2.5\times10^{-15}m}$$
$$=5.8\times10^5V$$
b. Conceptual Example 17.7 derives the potential energy of a pair of charges.
$$PE=\frac{1}{4\pi\epsilon_o}\frac{Q_1Q_2}{r}$$
$$=(8.99\times10^9\frac{N\cdot m^2}{C^2})\frac{(1.60\times10^{-19}C)^2}{2.5\times10^{-15}m}$$
$$=9.2\times10^{-14}J$$
This is about 0.58MeV.
