Answer
a) $v=9.03\times10^6\frac{m}{s}$
b) g is much smaller than a and can be considered insignificant
Work Step by Step
a) $\sum F=ma=qE$
$a=\frac{qE}{m}=\frac{(1.60\times10^{-19}C)(1.45\times10^4\frac{N}{C})}{9.11\times10^{-31}kg}=2.55\times10^{15}\frac{m}{s^2}$
$v^2=v_i^2+2a\Delta x$
$v=\sqrt{2(2.55\times10^{15}\frac{m}{s^2})(0.016m)}=9.03\times10^6\frac{m}{s}$
b) $a=2.55\times10^{15}\frac{m}{s^2}$
$g=9.8\frac{m}{s^2}$
g is much smaller than a and can be considered insignificant
