Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 15 - The Laws of Thermodynamics - Search and Learn - Page 442: 6

Answer

16 minutes for the photovoltaic panel, 3.3 minutes for the mirror.

Work Step by Step

Calculate the energy required to heat the water, equation 14–2. $$Q=mc\Delta T=(1.0kg)(4186 J/(kg \cdot C^{\circ})(70 C^{\circ}))=2.9302\times10^5 J$$ Use $1000 W/m^2$ as an estimate of the intensity of sunlight at the Earth’s surface. The 20 percent efficient photovoltaic panel has this power: $$\frac{Q}{t}=(1000W/m^2)(1.5m^2)(0.20)=300J/s$$ We divide the required energy by the power to find the time. $$t=\frac{Q}{Q/t}=\frac{2.9302\times10^5 J }{300J/s}=977s\approx 16 m$$ The curved mirror is 100 percent efficient, so it has this power: $$\frac{Q}{t}=(1000W/m^2)(1.5m^2) =1500J/s$$ We divide the required energy by the power to find the time. $$t=\frac{Q}{Q/t}=\frac{2.9302\times10^5 J }{1500J/s}=195s\approx 3.3 m$$
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