Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 13 - Temperature and Kinetic Theory - General Problems - Page 389: 87

Answer

The gravitational PE is much smaller.

Work Step by Step

The gravitational potential energy of a molecule is given by mgh. Its average kinetic energy is $\frac{3}{2}kT$. As requested, find the ratio of potential energy to kinetic energy. $$\frac{PE}{KE}=\frac{mgh}{1.5kT}=\frac{2(15.99)(1.66\times10^{-27}kg)(9.80m/s^2)(1.00m)}{1.5(1.38\times10^{-23}J/K)(296K)}=8.49\times10^{-5}$$ This is such a small ratio that the PE may be safely neglected.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.