Answer
290 m/s
9.5 m/s
Work Step by Step
The rms speed is given by equation 13–9.
Use the equation for an amino acid, at body temperature.
$$v_{rms}=\sqrt{\frac{3kT}{m}}=\sqrt{\frac{3(1.38\times10^{-23}J/K)(310K)}{89(1.66\times10^{-27}kg)}}\approx290m/s$$
Now apply it to the protein, also at body temperature.
$$v_{rms}=\sqrt{\frac{3kT}{m}}=\sqrt{\frac{3(1.38\times10^{-23}J/K)(310K)}{(8.5\times10^4)(1.66\times10^{-27}kg)}}\approx9.5m/s$$
