Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 12 - Sound - Problems - Page 355: 39

Answer

a. 55 Hz b. 190 m/s

Work Step by Step

a. The difference between consecutive overtones is 55 Hz. See Figure 12-11. For a pipe open at both ends, the difference is the fundamental frequency $f_1$, and the overtones are whole multiples of the fundamental frequency. b. See figure 12-11. For a pipe open at both ends, the fundamental frequency is $f_1=\frac{v}{2 \mathcal{l}}$. $$v=2 \mathcal{l}f_1=2(1.70m)(55Hz)=187m/s\approx 190m/s$$
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