Answer
1.2 m
Work Step by Step
For a closed tube, figure 12–12 shows that the lowest frequency $f_1=\frac{v}{4 \mathcal{l}}$. Assume the instrument is at room temperature so v = 343 m/s.
$$\mathcal{l}=\frac{v}{4f_1}=\frac{343m/s}{4(69Hz)}=1.2 m$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 12 - Sound - Problems - Page 355: 26
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