Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 12 - Sound - General Problems - Page 357: 73

Answer

88 dB.

Work Step by Step

Change the two sound level values to intensities. $$81 dB=10log\frac{I_{81}}{I_o}$$ $$ I_{81}=10^{8.1} I_o=1.259\times10^8I_o$$ $$87 dB=10log\frac{I_{87}}{I_o}$$ $$ I_{81}=10^{8.7} I_o=5.012\times10^8I_o$$ Now add the intensities, and find the sound level. $$I_{total}=(1.259\times10^8+5.012\times10^8)I_o=(6.271\times10^8)I_o$$ $$\beta_{total}=10log\frac{(6.271\times10^8)I_o}{I_o}=10(8.797)\approx 88dB$$
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