Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 11 - Oscillations and Waves - Problems - Page 324: 42

Answer

The depth of the ocean floor is 1.7 km

Work Step by Step

We can find the speed of the wave in sea water using the formula: $v = \sqrt{\frac{B}{\rho}}$ where $B$ is the Bulk modulus $\rho$ is the density Substituting the values and solving: $v = \sqrt{\frac{B}{\rho}}$ $v = \sqrt{\frac{2.0\times 10^9~N/m^2}{1.025\times 10^3~kg/m^3}}$ $v = 1.4\times 10^3~m/s$ Next, we find the distance the wave travels in 2.4 seconds: $d = v~t$ $d = (1.4\times 10^3~m/s)(2.4~s)$ $d = 3.4\times 10^3~m$ Since this distance $d$ is the total distance that the wave traveled, the depth of the ocean floor is half of this distance. $\frac{d}{2} = 1.7\times 10^3~m = 1.7~km$ The depth of the ocean floor is 1.7 km.
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