Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - Problems: 9


a. $6.1 \times 10^6 \frac{N}{m^2}$ b. $1.7 \times 10^5 \frac{N}{m^2}$

Work Step by Step

The downward force is equal to half the person’s weight. a. $P_{pointed}=\frac{(0.5)(56kg)(9.80m/s^2)}{0.45 \times 10^{-4}m^2}=6.1 \times 10^6 \frac{N}{m^2}$ b. $P_{flat}=\frac{(0.5)(56kg)(9.80m/s^2)}{16 \times 10^{-4}m^2}=1.7 \times 10^5 \frac{N}{m^2}$
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