Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - Problems: 20


$4.3 \times 10^5 N/m^2$

Work Step by Step

The minimum gauge pressure supports a column of water of this height. Use equation 10–3a, and round the answer to 2 significant figures. $$P_G=\rho gh = (1.00 \times 10^3 kg/m^3)(9.80 m/s^2)(44m)=4.3 \times 10^5 N/m^2$$
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