Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 38 - Quantization - Exercises and Problems - Page 1114: 20


$n = 6$

Work Step by Step

We can find the quantum number: $\lambda = \frac{2L}{n}$ $n = \frac{2L}{\lambda}$ $n = \frac{(2)(3.0~nm)}{1.0~nm}$ $n = 6$
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