Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 36 - Relativity - Exercises and Problems - Page 1060: 41

Answer

The ratio of the energy released in the star-antistar collision to the energy released in the supernova is $~~2400$

Work Step by Step

The mass of the sun is $2.0\times 10^{30}~kg$ We can find the energy released in the star-antistar collision: $E = mc^2$ $E = (2)(2.0\times 10^{30}~kg)(3.0\times 10^8~m/s)^2$ $E =3.6\times 10^{47}~J$ We can find the ratio: $\frac{3.6\times 10^{47}~J}{1.5\times 10^{44}~J} = 2400$ The ratio of the energy released in the star-antistar collision to the energy released in the supernova is $~~2400$
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