Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 36 - Relativity - Exercises and Problems - Page 1060: 38


$v = 0.417~c$

Work Step by Step

We can write an expression for the rest energy: $E = mc^2$ We can write an expression for the total energy: $E = \gamma ~mc^2$ If the total energy is 10% more than the rest energy, then $\gamma = 1.1$ We can find the speed when $\gamma = 1.1$: $\gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}$ $\sqrt{1-\frac{v^2}{c^2}} = \frac{1}{\gamma}$ $1-\frac{v^2}{c^2} = \frac{1}{\gamma^2}$ $\frac{v^2}{c^2} = 1-\frac{1}{\gamma^2}$ $v^2 = (1-\frac{1}{\gamma^2})~c^2$ $v = \sqrt{1-\frac{1}{\gamma^2}}~c$ $v = \sqrt{1-\frac{1}{1.1^2}}~c$ $v = \sqrt{0.1735537}~c$ $v = 0.417~c$
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