Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 33 - Wave Optics - Exercises and Problems - Page 956: 27

Answer

$L = 0.78~m$

Work Step by Step

We can find the required distance $L$: $w = \frac{2.44~\lambda~L}{d}$ $L = \frac{w~d}{2.44~\lambda}$ $L = \frac{(0.010~m)(0.12\times 10^{-3}~m)}{(2.44)~(633\times 10^{-9}~m)}$ $L = 0.78~m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.