Answer
$w = 4.88~mm$
Work Step by Step
We can find width of the central maximum:
$w = \frac{2.44~\lambda~L}{d}$
$w = \frac{(2.44)~(500\times 10^{-9}~m)(2.0~m)}{0.50\times 10^{-3}~m}$
$w = 4.88\times 10^{-3}~m$
$w = 4.88~mm$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 33 - Wave Optics - Exercises and Problems - Page 956: 25
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