Answer
$P = 395~W$
Work Step by Step
We can find the power:
$P = \epsilon_{rms}~I_{rms}~cos~\phi$
$P = (120~V)(3.5~A)~cos~20^{\circ}$
$P = 395~W$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 32 - AC Circuits - Exercises and Problems - Page 925: 37
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