Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 32 - AC Circuits - Exercises and Problems - Page 925: 36

Answer

$\phi = 30^{\circ}$

Work Step by Step

We can find the phase angle: $P = P_{max}~cos^2~\phi$ $0.75~P_{max} = P_{max}~cos^2~\phi$ $cos^2~\phi = 0.75$ $cos~\phi = \sqrt{0.75}$ $cos~\phi = 0.866$ $\phi = cos^{-1}~(0.866)$ $\phi = 30^{\circ}$
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