Answer
$C = 1.0\times 10^{-6}~F$
Work Step by Step
We can find the capacitance:
$I_d = C~(\frac{dv_c}{dt})$
$C = \frac{I_d}{\frac{dv_c}{dt}}$
$C = \frac{1.0~A}{1.0\times 10^6~V/s}$
$C = 1.0\times 10^{-6}~F$
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