Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 31 - Electromagnetic Fields and Waves - Exercises and Problems - Page 901: 9


$C = 1.0\times 10^{-6}~F$

Work Step by Step

We can find the capacitance: $I_d = C~(\frac{dv_c}{dt})$ $C = \frac{I_d}{\frac{dv_c}{dt}}$ $C = \frac{1.0~A}{1.0\times 10^6~V/s}$ $C = 1.0\times 10^{-6}~F$
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