Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 31 - Electromagnetic Fields and Waves - Exercises and Problems - Page 901: 10


$I_d = 1.7\times 10^{-5}~A$

Work Step by Step

We can find the capacitance: $C = \frac{\epsilon_0~A}{d}$ $C = \frac{\epsilon_0~\pi~r^2}{d}$ $C = \frac{(8.854\times 10^{-12}~F/m)~(\pi)~(0.025~m)^2}{0.50\times 10^{-3}~m}$ $C = 3.477\times 10^{-11}~F$ We can find the displacement current: $I_d = C~(\frac{dv_c}{dt})$ $I_d = (3.477\times 10^{-11}~F)~(500,000~V/s)$ $I_d = 1.7\times 10^{-5}~A$
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