Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 3 - Vectors and Coordinates Systems - Exercises and Problems: 38

Answer

$F_x = 451~N$ $F_y = 315~N$

Work Step by Step

Paul is pulling with a force $F$ that is directed at an angle of $\theta = 35^{\circ}$ above the ground. We can find the horizontal component of the force; $F_x = F~cos(\theta)$ $F_x = (550~N)~cos(35^{\circ})$ $F_x = 451~N$ We can find the horizontal component of the force; $F_y = F~sin(\theta)$ $F_y = (550~N)~sin(35^{\circ})$ $F_y = 315~N$
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