## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

$F_x = 77.1~N$ $F_y = 91.9~N$
$F_x = F~sin(\theta)$ $F_x = (120~N)~sin(40^{\circ})$ $F_x = 77.1~N$ $F_y = F~cos(\theta)$ $F_y = (120~N)~cos(40^{\circ})$ $F_y = 91.9~N$