Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 29 - The Magnetic Field - Exercises and Problems - Page 830: 9

Answer

(a) $B = 2.0\times 10^{-6}~T$ (b) 4.0%

Work Step by Step

(a) We can find the magnetic field at the point: $B = \frac{\mu_0~I}{2~\pi~r}$ $B = \frac{(4\pi\times 10^{-7}~T~m/A)~(200~A)}{(2~\pi)~(20~m)}$ $B = 2.0\times 10^{-6}~T$ (b) We can express this value as a percentage of the Earth's magnetic field: $\frac{2.0\times 10^{-6}~T}{50\times 10^{-6}~T}\times 100\% = 4.0\%$
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