Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 29 - The Magnetic Field - Exercises and Problems - Page 830: 6


$B = (0,0,-0.11~T)$

Work Step by Step

We can find the magnetic field at the point: $B = \frac{\mu_0~q~v~sin~\theta}{4~\pi~r^2}$ $B = \frac{(4\pi\times 10^7~H/m)~(1.6\times 10^{-19}~C)~(2.0\times 10^7~m/s)~sin~45^{\circ}}{(4~\pi)~(\sqrt{2}\times 0.010~m)^2}$ $B = 0.11~T$ By the right hand rule, the magnetic field is in the $-z$ direction. We can write the magnetic field as a vector: $B = (0,0,-0.11~T)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.