Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 28 - Fundamentals of Circuits - Exercises and Problems - Page 792: 42


(a) $E = 0.36~J$ (b) $Q = 8.0\times 10^{-4}~C$

Work Step by Step

(a) We can find the energy: $E = P~t $ $E = IVt$ $E = (0.80~A)(450~V)(1.0\times 10^{-3}~s)$ $E = 0.36~J$ (b) We can find the charge: $Q = I~t$ $Q = (0.80~A)(1.0\times 10^{-3}~s)$ $Q = 8.0\times 10^{-4}~C$
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