Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 28 - Fundamentals of Circuits - Exercises and Problems - Page 792: 40

Answer

(a) $\$14.40$ (b) It would take 34.7 months to recover the additional cost.

Work Step by Step

(a) We can find the cost of electricity for 30 days: $C_e = (\$0.10/kWh)(1.0~kW)(30\times 24~h)(0.20) = \$14.40$ (b) We can find the cost of electricity for 30 days for the more expensive refrigerator: $C_e = (\$0.10/kWh)(0.80~kW)(30\times 24~h)(0.20) = \$11.52$ We can save $\$2.88$ each month. We can find the number of months it takes to recover the additional cost: $\frac{\$100}{\$2.88} = 34.7$ It would take 34.7 months to recover the additional cost.
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