Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 28 - Fundamentals of Circuits - Exercises and Problems - Page 791: 26

Answer

The equivalent resistance between points a and b is $40~\Omega$

Work Step by Step

The equivalent resistance of the $10~\Omega$ and $40~\Omega$ resistors in series is $50~\Omega$ The equivalent resistance of the $55~\Omega$ and $20~\Omega$ resistors in series is $75~\Omega$ We can find the equivalent resistance $R_p$ of resistors in parallel: $\frac{1}{R_p} = \frac{1}{50~\Omega} + \frac{1}{75~\Omega}$ $\frac{1}{R_p} = \frac{3}{150~\Omega} + \frac{2}{150~\Omega}$ $\frac{1}{R_p} = \frac{5}{150~\Omega}$ $R_p = \frac{150~\Omega}{5}$ $R_p = 30~\Omega$ The equivalent resistance of $30~\Omega$ and the $10~\Omega$ resistor in series is $40~\Omega$ The equivalent resistance between points a and b is $40~\Omega$
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