Chapter 28 - Fundamentals of Circuits - Exercises and Problems - Page 790: 7

$R = 9.6~\Omega$ $I = 12.5~A$

We can find the resistance: $P = \frac{V^2}{R}$ $R = \frac{V^2}{P}$ $R = \frac{(120~V)^2}{1500~W}$ $R = 9.6~\Omega$ We can find the current: $I = \frac{V}{R} = \frac{120~V}{9.6~\Omega} = 12.5~A$