## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Across the $40~\Omega$ resistor, the potential difference is $20~V$ Across the $60~\Omega$ resistor, the potential difference is $30~V$
We can find the equivalent resistance of the two resistors in series: $R = 40~\Omega + 60~\Omega = 100~\Omega$ We can find the current in the circuit: $I = \frac{V}{R} = \frac{50~V}{100~\Omega} = 0.50~A$ We can find the potential difference across the $40~\Omega$ resistor: $\Delta V = I~R = (0.50~A)(40~\Omega) = 20~V$ We can find the potential difference across the $60~\Omega$ resistor: $\Delta V = I~R = (0.50~A)(60~\Omega) = 30~V$