#### Answer

$I = 1.65~A$

#### Work Step by Step

We can find the resistance:
$R = \frac{\rho~L}{A}$
$R = \frac{\rho~L}{\pi~r^2}$
$R = \frac{(3.5\times 10^{-5}~\Omega~m)(6.0\times 10^{-2}~m)}{(\pi)~(0.35\times 10^{-3}~m)^2}$
$R = 5.46~\Omega$
We can find the current:
$I = \frac{V}{R}$
$I = \frac{9.0~V}{5.46~\Omega}$
$I = 1.65~A$