Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 27 - Current and Resistance - Exercises and Problems - Page 763: 32


$R = 4.0\times 10^3~\Omega$

Work Step by Step

Note that: $~\rho = \frac{1}{\sigma}$ We can find the resistance: $R = \frac{\rho~L}{A}$ $R = \frac{L}{\sigma~A}$ $R = \frac{L}{\sigma~\pi~r^2}$ $R = \frac{0.20~m}{(0.63~S/m)(\pi)~(0.50\times 10^{-2}~m)^2}$ $R = 4.0\times 10^3~\Omega$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.