Answer
$R = 4.0\times 10^3~\Omega$
Work Step by Step
Note that: $~\rho = \frac{1}{\sigma}$
We can find the resistance:
$R = \frac{\rho~L}{A}$
$R = \frac{L}{\sigma~A}$
$R = \frac{L}{\sigma~\pi~r^2}$
$R = \frac{0.20~m}{(0.63~S/m)(\pi)~(0.50\times 10^{-2}~m)^2}$
$R = 4.0\times 10^3~\Omega$