Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 22 - Electric Charges and Forces - Exercises and Problems - Page 625: 39


$N = 8.4\times 10^{21}$

Work Step by Step

We can find the total charge delivered in 30 minutes: $Q = (-0.75~C/s)(30~min)(60~s/min) = -1350~C$ We can find the number of electrons: $N = \frac{-1350~C}{-1.6\times 10^{-19}~C} = 8.4\times 10^{21}$
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