Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 22 - Electric Charges and Forces - Exercises and Problems - Page 625: 23


$q_A = -8.0\times 10^{-8}~C$ $q_B = -8.0\times 10^{-8}~C$

Work Step by Step

Since the metal spheres are in contact, the electrons will spread around both spheres after the electrons are added to sphere A. Since the spheres are identical, half of the electrons will be on sphere A and half of the electrons will be on sphere B. We can find the charge on sphere A: $q_A = (\frac{1.0\times 10^{12}}{2})(-1.6\times 10^{-19}~C)$ $q_A = -8.0\times 10^{-8}~C$ Since the charge on sphere B is the same as the charge on sphere A, $q_B = -8.0\times 10^{-8}~C$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.