#### Answer

$V_1 = 200~cm^3$

#### Work Step by Step

We can find $V_1$ as:
$W = -P\Delta V$
$W = -P ~(V_f-V_i)$
$W = -P ~(V_1-3V_1)$
$W = 2P ~V_1$
$V_1 = \frac{W}{2P}$
$V_1 = \frac{80~J}{(2)(2.00\times 10^5~Pa)}$
$V_1 = 2.0\times 10^{-4}~m^3$
$V_1 = (2.0\times 10^{-4}~m^3)(\frac{10^6~cm^3}{1~m^3})$
$V_1 = 200~cm^3$