Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 19 - Work, Heat, and the First Law of Thermodynamics - Exercises and Problems: 15

Answer

$6900~J$ of heat energy must be added to the mercury.

Work Step by Step

The heat energy $Q$ required to change the temperature of a substance is: $Q = m~c~\Delta T$ The heat energy $Q$ required to change the state of a substance is: $Q = m~L$ We can find the heat energy required to change the mercury into mercury vapor. $Q = m~c~\Delta T + m~L$ $Q = (0.020~kg)(140~J/kg~C^{\circ})(357~^{\circ}C-20~^{\circ}C) + (0.020~kg)(2.96\times 10^5~J/kg)$ $Q = 6900~J$ $6900~J$ of heat energy must be added to the mercury.
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