Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 15 - Oscillations - Exercises and Problems: 32

Answer

$k = 0.079~N/m$

Work Step by Step

We can assume that the period is 1.0 s. We can find the spring constant of the silk thread. Therefore; $T = 2\pi~\sqrt{\frac{m}{k}}$ $k = \frac{(2\pi)^2~m}{T^2}$ $k = \frac{(2\pi)^2~(0.0020~kg)}{(1.0~s)^2}$ $k = 0.079~N/m$
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