Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 15 - Oscillations - Exercises and Problems: 24

Answer

$L = 0.99~m$

Work Step by Step

Note that the pendulum passes through the lowest point twice each cycle (once in each direction). For the clock to tick once each second, the period of the pendulum should be 2 seconds. We can find the length as: $T = 2\pi~\sqrt{\frac{L}{g}}$ $L = \frac{T^2~g}{(2\pi)^2}$ $L = \frac{(2~s)^2~(9.80~m/s^2)}{(2\pi)^2}$ $L = 0.99~m$
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