Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 13 - Newton's Theory of Gravity - Exercises and Problems - Page 354: 20


The radius of the event horizon is 14.7 km

Work Step by Step

We can use the equation for escape speed to find the radius $R$ of the event horizon. $v = \sqrt{\frac{2~G~M}{R}}$ $v^2 = \frac{2~G~M}{R}$ $R = \frac{2~G~M}{v^2}$ $R = \frac{(2)(6.67\times 10^{-11}~m^3/kg~s^2)(5.0)(1.99\times 10^{30}~kg)}{(3.00\times 10^8~m/s)^2}$ $R = 1.47\times 10^4~m$ $R = 14.7~km$ The radius of the event horizon is 14.7 km
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.