## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

We can use the equation for escape speed to find the escape speed from Jupiter. $v_{esc} = \sqrt{\frac{2~G~M}{R}}$ $v_{esc} = \sqrt{\frac{(2)(6.67\times 10^{-11}~m^3/kg~s^2)(1.90\times 10^{27}~kg)}{6.99\times 10^7~m}}$ $v_{esc} = 6.02\times 10^4 ~m/s$ $v_{esc} = 60.2 ~km/s$ The escape speed from Jupiter is 60.2 km/s